00:01
In this question we want to find out three values for four different angles.
00:05
So let's start with the first.
00:06
First for the angle, phi, which is equals to 90 degree.
00:11
We can write torque, thou.
00:13
That is the first quantity we want to find out, which is equals to mu b, sine, phi.
00:20
So it becomes here this n -l, sorry, n -i -a, b, sine, 90 degree, correct? on simplification, it becomes n, i, a, b, because sine nt degree is 1, this n is the number of turn, i is the current a is the area, and b is the magnetic field.
00:43
Now we want to find out the direction of torque, so we can write the direction of torque tau which is equals to mu cross b.
00:51
Now here, this mu has a direction, k in the k direction and this b is in the direction of so we get the direction of torque is minus i cap.
01:06
This is the direction of torque.
01:08
Then the next we want to find out the value of potential energy for this.
01:13
So u which is equal to minus mu b, cos theta, cos phi...