33 \, \mathrm{T}$:
Given $B(t) = 0.380 \, \mathrm{T/s^3} \cdot t^3$, we can set $B(t) = 1.33 \, \mathrm{T}$ and solve for $t$:
$0.380 \, \mathrm{T/s^3} \cdot t^3 = 1.33 \, \mathrm{T}$
$t^3 = \frac{1.33}{0.380}$
$t = \left(\frac{1.33}{0.380}\right)^{1/3}$
$t \approx
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