A coaxial conductor has an inner radius $a = 1.0 \text{ mm}$ and an outer radius $b = 5 \text{ mm}$. The dielectric between the two conductors is silicon. The polarization field $P$ within the dielectric is given by $P = \frac{2}{\rho^2} a \rho \frac{nC}{m^2}$ (a) Find $D$ and $E$ as functions of $\rho$. (b) Find $V_{ab}$.
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In a linear dielectric material, this relationship is given by D = ε0E + P, where ε0 is the permittivity of free space and E is the electric field. Since the dielectric is silicon, we can use the permittivity of silicon (εr = 11.7) to find ε0 = εrε0, where ε0 is Show more…
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