Question

A coffee maker can be modeled as a heating element (resistance R) connected to the outlet voltage of 120.0 V (assumed to be dc). The heating element boils small amounts of water at a time as it brews the coffee. When bubbles of water vapor form, they carry liquid water up through the tubing. Because of this, the coffee maker boils 1.60% of the water that passes through it; the rest is heated to 100°C but remains liquid. Starting with water at 10.0°C, the coffee maker can brew 1.00 L of coffee in 7.70 min. Find the resistance R. The latent heat of vaporization of water is 2,256,000 J/kg and the specific heat of water is 4186 J/ (kg·K).

Name: a coffee maker can be modeled as a heating element resistance r connected to the outlet voltage of 1200 v assumed to be dc the heating element boils small amounts of water at a time as it br 81661
Uploaded: 2022-02-28T12:13:51-08:00
Duration: 2 min 32 s
Channel: Aniket Bajaj
Description: a coffee maker can be modeled as a heating element resistance r connected to the outlet voltage of 1200 v assumed to be dc the heating element boils small amounts of water at a time as it br 81661

          A coffee maker can be modeled as a heating element (resistance
R) connected to the outlet voltage of 120.0 V (assumed to be dc).
The heating element boils small amounts of water at a time as it
brews the coffee. When bubbles of water vapor form, they carry
liquid water up through the tubing. Because of this, the coffee
maker boils 1.60% of the water that passes through it; the rest is
heated to 100°C but remains liquid. Starting with water at 10.0°C,
the coffee maker can brew 1.00 L of coffee in 7.70 min. Find the
resistance R. The latent heat of vaporization of water is 2,256,000
J/kg and the specific heat of water is 4186 J/ (kg·K).

Added by Tanya B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Aniket Bajaj

02/28/2022

Step 1

5 kg of water from 23°C to 100°C. Given: Mass of water (m) = 0.5 kg Specific heat of water (C) = 4186 J/(kg·K) Initial temperature (T1) = 23°C Final temperature (T2) = 100°C Use the formula Q = m * C * ΔT, where ΔT = T2 - T1 Q = 0.5 kg * 4186 J/(kg·K) * (100°C - Show more…

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A coffee maker can be modeled as a heating element (resistance R) connected to the outlet voltage of 120.0 V (assumed to be dc). The heating element boils small amounts of water at a time as it brews the coffee. When bubbles of water vapor form, they carry liquid water up through the tubing. Because of this, the coffee maker boils 1.60% of the water that passes through it; the rest is heated to 100°C but remains liquid. Starting with water at 10.0°C, the coffee maker can brew 1.00 L of coffee in 7.70 min. Find the resistance R. The latent heat of vaporization of water is 2,256,000 J/kg and the specific heat of water is 4186 J/ (kg·K).