Given:
Number of turns, $N = 120$
Current, $I = 0.490$ A
Radius of the coil, $r = 0.048$ m
The magnetic moment, $\mu$, is given by:
$$\mu = N \cdot I \cdot \text{Area}$$
$$\text{Area} = \pi r^2$$
$$\mu = 120 \times 0.490 \times \pi \times (0.048)^2$$
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