Given:
Length of wire, L = 25.0 m
Current, I = 0.500 A
Using Ohm's Law, V = IR, where V is the potential difference.
V = 0.500 A * 1 Ω = 1 V
Electric field, E = V / L
E = 1 V / 25.0 m = 0.04 V/m
Therefore, the magnitude of the electric field in the wire is
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