00:01
In this question it is given that there is a coin and this coin is moving in a circular path.
00:11
The distance of the coin from the center of the path is r.
00:19
When the coin is rotating in a circular path on the rotating table, then a centripetal force is necessary on the coin so that it can rotate in a circular path.
00:32
This centripetal force is provided by the frictional force on the coin.
00:37
So we can write the centripetal force on the coin is mu times m g and this frictional force is equal to the centripetal force on the coin.
00:52
M r into the angular velocity of the coin omega square.
01:01
M is the coefficient of friction.
01:04
M is the mass and g is the acceleration due to gravity.
01:07
So these three are the constants.
01:10
So we can write the first distance of the coin from the center r1 divided by r2 is equal to omega 1, omega 2, sorry, omega 2 square divided by omega 1 square.
01:44
Now we have to find the value of r2...