00:01
So, here we have been given with a combustion analysis and here it is said that the analysis produces 7 .69 gram of co2 and 3 .17 gram of h2o.
00:22
So we have also been given that the molar mass of the compound was identified as 56 .107 gram per mole.
00:33
So corresponding to that, we have to determine the molecular formula of the compound.
00:43
So here if we see then the moles of co2 would be equal to the given mass which is 7 .69 gram divided by 44 gram mole inverse, which is the molar mass of co2, which is equal to 0 .1748 so now if we see then the moles of carbon would be equal to the moles of co2 here, which is equal to 0 .1748 moles.
01:20
Now if we calculate the moles of water, that is h2o, so it is equal to 3 .17 gram divided by molar mass 18 gram mole inverse.
01:29
So, it is equal to 0 .1761 moles.
01:36
Now here, if we see the moles of hydrogen, so it would be equal to 2 multiplied by the moles of h2o, which is 0 .1761.
01:49
So it is equal to 0 .3522 moles...