67 \times 10^{-11} \, \text{m}^3 \, \text{kg}^{-1} \, \text{s}^{-2}$
- Mass of the Sun, M = $1.989 \times 10^{30} \, \text{kg}$
- Time period of the comet, T = 79.6 years = $2.514 \times 10^9$ seconds
- $\pi \approx 3.14$
Using Kepler's third law: $a^3 = \frac{G
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