00:01
So i see that you need help with this problem, and it says a commercial store is planning to advertise in different outlets to maximize the number of customers reached.
00:08
There are three possible outlets to choose from, tv, radio, and magazines.
00:12
Each ad on tv, radio, and magazines reaches the following number of people and millions.
00:18
The budget is, so we have a budget, and that's of $10 ,000.
00:26
There cannot be more than five tv ads total.
00:29
So if i do five times 600, okay, that is $3 ,000.
00:44
Okay.
00:45
And then the total number of ads should be between 15 and 25.
00:52
So between 15 and 25 ads.
00:57
Okay.
00:59
So then plus we would have some.
01:07
Something so then what i would do next is radio as much as i can so i have 7 ,000 left divided by 300 so if i if that's so plus 300 x plus then and i want to use the maximum amount 500 y equals 10 ,000 and so what i would do is if i have this much left.
02:02
Okay, so then what i would do is if i do 300 times 15, so 300 times 15, that's 4 ,500.
02:19
So that's 15.
02:20
So that's 4 ,500.
02:22
So right now i have 7 ,500.
02:26
500 minus or 10 ,000 minus 7 ,500 and that is 2 ,500 left over divided by 25...