This can be done using combinations, which is denoted as $_nC_r$ or $C(n, r)$, where $n$ is the total number of items and $r$ is the number of items to choose. In this case, we have:
$$C(17, 3) = \frac{17!}{3!(17-3)!} = \frac{17!}{3!14!}$$
Now, we need to find
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