a company pays its employees and average hourly wage of 36.25 with a standard deviation of 6.50 more than 23.22 of 36 employees are randomly selected, what is the probability that their mean wage is more than 23.22
Added by Caleb M.
Step 1
22: \[ z = \frac{23.22 - 36.25}{6.50/\sqrt{36}} = \frac{-13.03}{1.0833} \approx -12.0277 \] Show more…
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