00:01
So in this question, for the first part of the question, it says that a compound contains only nitrogen and oxygen.
00:10
A nitrogen is 36 .84 % by mass.
00:14
So what is the empirical formula of this compound? so let's solve it.
00:22
So in solving for the empirical formula, we divide, we know that nitrogen has a mass percentage of 36 .84 percent.
00:41
And oxygen is equal to 100 minus 36 .84 which is equal to 63 .16%.
00:55
So in serving for the empirical formula, we divide the mass percentage of each element by each molar mass.
01:04
So we have nitrogen, which is equal to 36 .84, divided by 8 molar mass 14.
01:13
That will give us an answer of 2 .63.
01:19
Then we have oxygen with mass percentage of 63 .16 divided by 8 molar mass which is 16.
01:31
That will give us an answer of 3 .95.
01:38
So we divide each value by the least common value.
01:41
So our least common value is 2 .63.
01:44
So 2 .63 divided by 2 .663 is equal to 1 and then 3 .95 divided by 2 .63 is equal to 1 .5 times 2 which is equal to 3 and then 1 times 2 is equal to 2.
02:05
So therefore our empirical formula for this compound is n203...