00:01
Dear students, as per the question a compound has 9 .09 gram carbon, 1 .52 gram hydrogen, 14 .4 gram fluorine.
00:14
We have to find out its molecular formula and if the compound has a molecular mass of 66 gram per mole, then what is its molecular formula.
00:25
So we have to find out empirical formula and molecular formula for the compound.
00:31
So let us see first the masses of the elements given.
00:36
Let us find out the relative number of atoms, carbon, hydrogen, fluorine.
00:43
Carbon is 9 .09 gram, in gram here.
00:49
Hydrogen is 1 .52 gram and fluorine is 14 .4 gram.
00:56
So by dividing with their atomic masses, let us find out relative number of atoms.
01:09
So 9 .09 divided by 12, this is 1 .52 divided by 1, this is 14 .4 divided by 19.
01:21
So relative number of atoms of carbon comes 0 .76, hydrogen 1 .52 and fluorine 0 .76.
01:31
Now simplest ratio we will find out...