Question

A compound thin cylinder has a common diameter of 100 mm, and the inner cylinder has a thickness of 2.5 mm. The radial pressure between the two cylinders is 200 kPa, and the difference between the two common diameters before shrinkage was 0.004305 mm. E = 200 GPa.

Name: a compound thin cylinder has a common diameter of 100 mm and the inner cylinder has a thickness of 25 mm the radial pressure between the two cylinders is 200 kpa and the difference between t 44085
Uploaded: 2023-07-12T03:55:13-08:00
Duration: 2 min 25 s
Channel: Madhur L
Description: a compound thin cylinder has a common diameter of 100 mm and the inner cylinder has a thickness of 25 mm the radial pressure between the two cylinders is 200 kpa and the difference between t 44085

          A compound thin cylinder has a common diameter of 100 mm, and the inner cylinder has a thickness of 2.5 mm. The radial pressure between the two cylinders is 200 kPa, and the difference between the two common diameters before shrinkage was 0.004305 mm. E = 200 GPa.

Added by Emily E.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

07/12/2023

Step 1

Calculate the original outer diameter of the cylinder: The difference between the two common diameters before shrinkage was 0.004305 mm, so the original outer diameter is: D_outer = 100 + 0.004305 = 100.004305 mm Show more…

Show all steps

Thanks for your feedback!

A compound thin cylinder has a common diameter of 100 mm, and the inner cylinder has a thickness of 2.5 mm. The radial pressure between the two cylinders is 200 kPa, and the difference between the two common diameters before shrinkage was 0.004305 mm. E = 200 GPa.