00:01
Okay, so i see that you need help with this question.
00:02
It says a computer manufacturer company has sent an email survey to 2 ,800 of its randomly selected customers that have purchased a laptop.
00:10
The survey asked customers whether or not they were satisfied with the computer.
00:18
Eight hundred responded to the survey.
00:22
So, 800 responses.
00:27
Six hundred forty indicated that they were satisfied.
00:33
Well, 160 indicated not satisfied.
00:36
Construct a 96 % confidence interval estimate of the true proportion of customers satisfied with their new computer.
00:48
So, that's 640 out of 800.
00:51
So, that's 640 divided by 800.
00:55
That's 0 .8 plus or minus.
01:00
And so, for 96 % confidence interval, that is a z score of 2 .05.
01:06
So, 2 .05 times the square root of 0 .8 times 0 .2 divided by 800...