00:01
For the inside this sphere, inside this sphere, r is less than a where a is the radius of the sphere and r is the distance of the sphere.
00:15
And outside the sphere, in the second part, outside the sphere where r is much, much greater than a.
00:24
So for the first part of the equation, let's solve.
00:27
Electric field inside the sphere where r is less than a.
00:29
So applying gos law, that is integration e vector dot d .s vector would be given.
00:36
By q enclosed divided by e.
00:39
Where e is the electric field, a is the surface area, surface area, e.
00:44
D .s is the flux, qnclose is the charge enclosed by the caution surface, e is the permittivity.
00:49
Now for r less than a, no charge enclosed.
00:56
So q enclose would be equal to 0.
00:58
So e .d .s.
01:01
Cos theta would be equal to 0...