00:01
Using the data in exercise 23, we are going to calculate the average velocity delta y over delta x on each sub interval of length 0 .5.
00:17
Then we're going to construct a table of two columns.
00:21
In the first column, we will have the midpoints of the subinterables.
00:26
And in the second column, it will contain the average velocities.
00:34
That's part a.
00:35
In part b, we are going to find a linear regression model for data on the table constructed in par a.
00:42
And then we are going to make a plot of that data and the linear regression.
00:47
And in part c, we will use model found in part c to approximate the velocity of the ball at 1 .5 seconds.
00:56
And we will compare that with exercise 23 part d, where we made a calculation of the velocity of the ball at that time.
01:05
With a different approach so here we have the table of the exercise 23 we remember in that exercise the ball was was released from the roof of a building and then each 0 .5 seconds the height or distance from the above the ground and from the ground to the ball was measured in feet so we have have time seconds, height and feet, and for each 0 .5, we have those measures found here.
01:54
So now we are going to construct for each interval of length 0 .5, we will have, we will find, or calculate the average velocity.
02:03
Those intervals are from 0 to 0 .5, 0 .5 to 1, 1 to 1 .5, and so on, until the interval from 5 to 5 .5.
02:20
So that's the data we're going to construct now in part a.
02:26
So let's do, for example, the calculations for the interval 0 .5.
02:36
So there we will have first the midpoint.
02:42
And this is the average of the endpoints of this interval.
02:46
That is 0 plus 0 .5 over 2...