A constant force acts on a body of mass 0.9 kg at rest for 10s. If the body moves a distance of 250 m, the magnitude of the force is (a) 3N (b) 3.5N (c) 4.0N (d) 4.5N
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Step 1
We know that the body was initially at rest and it moved a distance of 250 m in 10 seconds. We can use the equation of motion: s = ut + 0.5at^2 where s is the distance, u is the initial velocity, a is the acceleration, and t is the time. Since the body was Show more…
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