0:00
Let's solve the question.
00:01
So, we write dt divided by dv is equal to 9 .5v plus 8 .3.
00:09
So, this is the first.
00:11
Now, dt divided by dv is equal to alpha mu c divided by a square d it is delta p plus mu r divided by a delta p.
00:31
Now, integrating the equation dt is equal to 9 .5v plus 8 .3 multiplied by dv.
00:41
Now, p will be equal to 9 .5 divided by 2 v square plus 8 .3 v or t divided by v is equal to 4 .75 plus 8 .3.
00:58
So, 9 .5 divided by 2 that will be equal to mu c divided by a square multiplied by alpha divided by delta p that will be equal to 4 .75.
01:13
So, mu r divided by a delta p that will be equal to 8 .3.
01:20
Now, here the cake resistance is increased by 20 percent.
01:27
So, therefore, alpha 2 that will be equal to 1 .2 alpha 1...