00:01
So if we have two cars and we try and find the probability that neither will need repair, both will need repair, and at least one car will need repair, what do we do? well, first we're told that 16 % of cars will need at least one repair.
00:19
5 % will need two repairs.
00:26
And 4 % will require three repairs.
00:32
So for our first part, neither will need repair.
00:36
Assuming that both cars are equal in the probability of having repairs, meaning that they both have the same chances of repairs, we can, for both of them, multiply 100 minus the probabilities of needing repairs.
00:56
Do this twice, so we multiply them together.
00:59
This is car 1, and this is car 2.
01:03
Then we just divide this by 100 to signify a percentage.
01:13
So we will have, i believe, 100 minus 16, minus 5, minus 4, that is 75 times 75, divided by 100 is equal to 56 .25%.
01:38
This is assuming that both cards are equal to 56 .25%.
01:43
Equally likely to need repairs or not need repairs.
01:50
What i mean there is that car one is this, and then car two is also 16, 5, and 4.
01:57
We don't have for a car 2, something like 20, 10, and then 5...