00:01
In our question we are given that a container has a vertical tube whose inner radius is of 24mm it is connected to its side as shown in our figure.
00:11
Now an unknown liquid reaches level a in the container and level b in the tube level.
00:17
Now a being 5 centimetres higher than level b.
00:20
The liquid also supports a 20 centimetre high column of oil between levels b and c.
00:26
We need to determine whose density is the mass of the oil.
00:30
Oil closes to.
00:32
Now in order to find the mass of the oil, consider pressure being equivalent to rho, j, h.
00:39
Where row is the density, g acceleration due to gravity and h the height.
00:43
Now the height between point a to b, let it be h1, is 5 centimetres, which will be equal to 0 .05 meters.
00:57
And the height between point b to c is given to us as 20 centimeters which we can write as 0 .2 meters.
01:08
Therefore there are two pressures, p1 and p2, where p1 will be equivalent to row 1, h1, g and p2 pressure will be equal to row 2 h2...