Question

A coordinate system (in meters) is constructed on the surface of a pool table, and three objects are placed on the table as follows: a $m_1$ = 1.9-kg object at the origin of the coordinate system, a $m_2$ = 3.3-kg object at (0, 2.0), and a $m_3$ = 5.2-kg object at (4.0, 0). Find the resultant gravitational force exerted by the other two objects on the object at the origin.

Name: A coordinate system (in meters) is constructed on the surface of a pool table, and three objects are placed on the table as follows: a m1 = 1.9-kg object at the origin of the coordinate system, a m2 = 3.3-kg object at (0, 2.0), and a m3 = 5.2-kg object at (4.0, 0). Find the resultant gravitational force exerted by the other two objects on the object at the origin.
Uploaded: 2021-12-01T05:10:57-08:00
Duration: 2 min 56 s
Channel: Tatiana Graham
Description: A coordinate system (in meters) is constructed on the surface of a pool table, and three objects are placed on the table as follows: a m1 = 1.9-kg object at the origin of the coordinate system, a m2 = 3.3-kg object at (0, 2.0), and a m3 = 5.2-kg object at (4.0, 0). Find the resultant gravitational force exerted by the other two objects on the object at the origin.

          A coordinate system (in meters) is constructed on the surface of a pool table, and three objects are placed on the table as follows: a $m_1$ = 1.9-kg object at the origin of the coordinate system, a $m_2$ = 3.3-kg object at (0, 2.0), and a $m_3$ = 5.2-kg object at (4.0, 0). Find the resultant gravitational force exerted by the other two objects on the object at the origin.

A coordinate system (in meters) is constructed on the surface of a pool table, and three objects are placed on the table as follows: a m1 = 1.9-kg object at the origin of the coordinate system, a m2 = 3.3-kg object at (0, 2.0), and a m3 = 5.2-kg object at (4.0, 0). Find the resultant gravitational force exerted by the other two objects on the object at the origin.

Added by Kelly D.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Tatiana Graham

12/01/2021

Step 1

674 \times 10^{-11} \text{ N m}^2/\text{kg}^2$ be the gravitational constant. The force exerted by $m_2$ on $m_1$ is given by: $$F_{21} = G \frac{m_1 m_2}{r_{21}^2}$$ where $r_{21} = 2.0$ m is the distance between $m_1$ and $m_2$. $$F_{21} = 6.674 \times 10^{-11} Show more…

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A coordinate system (in meters) is constructed on the surface of a pool table, and three objects are placed on the table as follows: a $m_1 = 1.9$-kg object at the origin of the coordinate system, a $m_2 = 3.3$-kg object at (0, 2.0), and a $m_3 = 5.2$-kg object at (4.0, 0). Find the resultant gravitational force exerted by the other two objects on the object at the origin.