00:01
Let us begin with subpart a.
00:05
We have the velocity of cosmic ray electron given as 5 .9 into 10 power 6 meter per second.
00:15
The magnetic field strength is given as 1 .7 into 10 power minus 5 tesla.
00:22
The mass of the electron is 9 .11 into 10 power minus 31 kilograms.
00:30
The charge of the electrode is minus 1 .6 into 10.
00:34
10 power minus 90 columns.
00:40
Now in the first subpart it is asked to calculate the magnitude of magnetic force of electron which is given by f equals qvb.
00:51
Now substitute the given values that is f equals 1 .6 into 10 power minus 19 columns into 5 .9 into 10 power 6 meter per second into 1 .7 into 10.
01:07
10 power minus 5 tesla.
01:10
This will give a value of 1 .605 into 10 power minus 17 newton.
01:18
Therefore, the magnitude of magnetic force on the electron is calculated as 1 .605 into 10 power minus 17 newton.
01:31
This is the answer for subpart 8.
01:36
Now let us move on to subart c...