00:01
Now here in this problem, we are given that a crate that has a mass of 9 .2 kg is pulled up a rough inclined plane with an initial speed of 1 .52 m per second and to pull it we are applying a force of 102 n parallel to the incline.
00:25
Applied force is 102 n.
00:28
This force make an angle 20 .3 degrees with the horizontal.
00:33
Now the coefficient of kinetic friction is given to be 0 .40.
00:41
Now the crate is pulled over a distance of 4 .98 m.
00:47
Our task is to find that what is the work done by the gravitational force on the crate.
00:54
So let me first picturize this.
00:57
Suppose this is an inclined plane.
01:01
Now this is the horizontal surface.
01:05
Now this is the crate here.
01:08
Applied force is f.
01:10
So this is the direction for f.
01:12
Now this force make an angle 20 .3 degrees with the horizontal.
01:16
Basically this angle is given to be 20 .3 degrees.
01:20
Now then the gravity force would be acting vertically downward.
01:28
This would be the gravity force.
01:30
And if i take this plane which is perpendicular to the surface, inclined surface.
01:37
So here we have this normal force n.
01:42
Correct? and the friction would be acting in the opposite direction of motion...