A crude model of the human vocal tract treats it as a pipe closed at one end. Find the effective length of the vocal tract in a person whose fundamental tone is 620 Hz. Sound of speed in air at body temperature is 354 m/s.
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We know that the fundamental frequency of a pipe closed at one end is given by the formula: f1 = (v / 4L) where f1 is the fundamental frequency, v is the speed of sound in the medium, and L is the effective length of the pipe. Show more…
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A crude model of the human vocal tract treats it as a pipe closed at one end. Find the effective length of a vocal tract whose fundamental tone is $620 \mathrm{Hz}$. Take $V_{\text {sound }}=354 \mathrm{m} / \mathrm{s}$ at body temperature.
A crude model of the human vocal tract treats it as a pipe closed at one end. Find the effective length of the vocal tract in a person whose fundamental tone is $620 \mathrm{~Hz}$. Assume air at body temperature. Note: Variations in the shape of the mouth and position of the tongue significantly alter this simple model.
If a human ear canal can be thought of as resembling an organ pipe, closed at one end, that resonates at a fundamental frequency of $3000 \mathrm{Hz}$, what is the length of the canal? Use a normal body temperature of $37^{\circ} \mathrm{C}$ for your determination of the speed of sound in the canal.
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