A current of 0.500 Amp is passed through an electrolytic cell containing molten MgCl2 for 2.00 hours. The reduction reaction is: Mg2+ + 2 e- → Mg (s). Calculate the mass of Mg metal formed at the cathode. 0.907 g 3.07 x 10^-3 g 0.453 g 1.81 g
Added by Karen B.
Step 1
We can use the equation Q = I * t, where Q is the charge, I is the current, and t is the time. Given: I = 0.500 Amp t = 2.00 hours Converting hours to seconds: t = 2.00 hours * 3600 seconds/hour = 7200 seconds Q = 0.500 Amp * 7200 seconds = 3600 Coulombs Show more…
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