The circumference of the loop is given as $2.00 \mathrm{~m}$, so the radius of the loop is $r = \frac{2.00 \mathrm{~m}}{2\pi} \approx 0.318 \mathrm{~m}$. Therefore, the area of the loop is $A = \pi r^2 \approx 0.318^2 \pi \mathrm{~m^2} \approx 0.318
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