The Hall electric field is given by the formula:
$E_H = \frac{V_H}{t}$, where $V_H$ is the Hall voltage and $t$ is the thickness of the strip.
Given $V_H = 5 \times 10^{-4}$ V and $t = 0.005$ m.
$E_H = \frac{5 \times 10^{-4}}{0.005} = 0.1$ V/m
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