A cyclic process involving 10 mole of ideal gas is shown in...

A cyclic process involving 1.0 mole of ideal gas is shown in (Figure 1). A)Determine the work done on the gas by the environment during each step of the cycle. B) Determine the net work done on the gas WEnvonGas. C) Find the work that the gas does on the environment; it is equal to WGasonEnv=?WEnvonGas. D)Use the ideal gas law to determine the temperature of the gas at each corner of the process (1, 2, 3, and 4). E)Determine the thermal energy of the gas at each corner of the process.

Transcript

00:01 Alright, so here, let plot the process here.

00:04 So if this is the process, right? the process is not shown in the figure, but let if this is the process, right? let if this is the process, right? so let this is a cyclic process, right? this is a cyclic process, right? and which has a one mole right so this is one two three four right and here this is volume n meter cube right and this is pressure at kilo pascal right now in part a we will let in part a calculate the let in part a calculate the work done right or work done right so at the process from 1 to 2 it is azo baric process right this is azobaric process right so the work done of gas on the environment right this is p change in volume this is 120 times 10 to the power 3 time 4 minus 1 this is 360 kilojoules right so the negative work done are the work done by the environment on gas this is negative 360 kilojol right and this is the work done of gas by then on the environment right now in process let in process 2 to 3 3 and process 4 to 1 this is isochoric process right isochoric this is azeochorex process these two are isochoric process and the change in volumes are 0 right so work done from 2 to 3 and work done from 4 to 1 this is 0 right and again, in the process, pram three to poor, right? from three to four, this process is is a baryc process, right? isobaric process.

02:58 So the work done of gas in the environment, this is, change in volume, this is 61 minus 4.

03:10 This is minus 180 kilojol, right? now work done by the environment on gas this is positive 180 kilojoules right now in part b here in part b the network done by the environment on gas by the environment and gas is minus 360 plus 180 this is minus 180 kilojolz right and part c the network done by guess or environment right by guess and environment this is minus guess this is plus 180 kilojoules positive work done right now in part d we know that pv is equal to nr t so at point one this is p1 v1 this is n r t 1 and this is n r t 1 and t1 will be this is the thermal energy are this is just so t1 lit lit t1 will be p1 v1 over r t4 right so this will be 120 times 10 to the power two times one over 8 .314 times one this is 143 .3 .5 kil1 right right now at point two there will be p2 v2 will be in r t2 so t2 will be p2 v2 over n r right this is r right this is r right this is r right so now uh now this is uh if we put the way this is 128 .314 right so this will t2 will be thousand seven three four kilone now at point three here this will be p3 v3 this will be in r t3 right so t3 will be p3 v3 over nr right so this will be 60 times 10 to the power three times four over 8 .331 4 times 1 so this t3 will be 28 ,867 kilvin right now 8 .4, this will be p4, v4, this will be nr t4, right? this is 8 .4.

06:24 So here t4 will be p4 v4 over nr, right? so this will be 60 times 1 times 10 to the power 3 over 1 times 8 .3 ,1 4.

06:39 So t4 will be 7 ,216 .8 kilvens, right? now the thermal energy is in part e the thermal energy is let thermal energy is let thermal this is the last part right so thermal energy is 3 over 2 rt right and 8 .1 v1 is 3 over 2 rt1 right so this is 3 over 2 r t 1...

Question

Please give Ace some feedback