A cyclist coasts up a 6.00° slope, traveling 15.0 m along...

A cyclist coasts up a 6.00° slope, traveling 15.0 m along the road to the top of the hill. If the cyclist's initial speed is 8.75 m/s, what is the final speed? Ignore friction and air resistance. Part 1 + To solve this problem it will be necessary to first calculate the change in height from the bottom of the hill to the top. Find the change in height from the bottom of the hill to the top. Part 2 If the cyclist's initial speed is 8.75 m/s, what is the final speed?

Transcript

0:00 Hello everyone.

00:01 According to this question, the solution as follows.

00:05 Here they have given a data that is initial velocity that i will take as v0 is equals to 11 meter per second.

00:18 And also they have given height of the hill is 5 meter.

00:27 And to find the velocity here what we can do, we can even.

00:34 Use a conservation of energy or mechanical energy.

00:39 So we can say here using the conservation of mechanical energy, mechanical energy, we can say that is going to become, we know initial kinetic energy.

01:11 First we'll mention here, initial kinetic energy.

01:20 Initial kinetic energy, initial kinetic energy, is equal to half mv0 square similarly potential energy at the top potential energy at the top of the hill at the top of the hill is mgh and remaining kinetic energy because it is moving so remaining kinetic energy is equal to half mv square using these three point we can write conservation of mechanical energy as half mv not square is equals to half mv square plus m gh here both the side mass is going to cancel so we are getting v not square by two is equal to v square by 2 plus g into h so we need to find v square here i mean v we have to find then we can write this term as v square by 2 is equals to v0 square by 2 minus g h here substitute v not the given 11 square that divided by and here g acceleration due to gravity i will take this is 9 .8 into height is 5 then it is going to become answer v square by 2 simplify this answer is the 11 .5 that is v square by 2 similarly then v square we can mention 23 or v is equal to 4 4 .8 meter per second.

04:03 So this will be the velocity.

04:08 Okay...

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