00:01
The radius of the cyclotron is equal to 0 .450 meter.
00:05
The potential difference through which the protons are accelerated, that is delta v, is equal to 600 volt.
00:11
And the magnitude of the magnetic field, b, is equals to 0 .690 tesla.
00:16
And the mass of the proton, m, is equal to 1 .67, multiplied by 10 .h2 .m.
00:22
Minus 27 kg.
00:24
And the charge of the proton q is created.
00:31
For the a part of the equation, the size of the equation, the size.
00:34
Cyclotron frequency omega is equal to qb divided by mp so we would put the values into this equation we would have 1 .6 multiplied by 10 x to power minus 19 coulum multiplied by the value of b which is 0 .690 tesla whole divided by mp which is 1 .67 multiplied by 10 to power minus 27 kg and we solve this we get the value for a part of the equation that is omega is equal to 66 .10 multiplied by 10 x2 power 6 radian divided by seconds as the answer for the a part of the equation.
01:08
Now for the b part of the equation, we would have the speed at which proton exit the cyclotron is given by mp v divided by p is equal to bq or we can say v to be equal to bqr divided by mp...