00:01
When the charge ultrek moves in a region of magnetic field, it follows a circular path, which rate with the specific radius.
00:08
We can solve for the magnetic field strength using the following formula, where n is the mass, b is the speed, q is the charge, and r is the regions of that.
00:18
B is the magnetic field strength expressed in tesla.
00:21
In this problem, we are given with a cyclotron that is operated with an oscillator frequency of 12 megahertz, and as a radius of 53 centimeters.
00:30
We want to find the magnitude of the magnetic field needed for deuterons be accelerated in the said cyclotone as well as the kinetic energy of the jeterons.
00:43
Now, jeteron is a proton with a mass of twice the mass of proton.
00:48
Its charge is equal to the charge of proton, which is 1 .609 times 10 to the negative 19 .000.
00:54
As the mass of one proton is 1 .673 times 10 to the power of negative 27.
01:01
Thus, the mass of deuterol would be twice of these.
01:04
So we will have it as 3 .35 times 10 to the negative 27.
01:18
So first is that we will find you b, the magnetic field straight, using the formula that we use here.
01:27
So we note that the frequency of oscillation can also be expressed in terms of the speed as follows.
01:34
Over 2 .5r.
01:37
This is this formula suggests that we have to divide the speed of the speed of the charged particle divided by the distance.
01:49
So that distance is the circumference of the circle with a specific radius of r...