00:01
In the first question, a cylinder of nitrogen gas is given having the number of mole and is equal to 23 .5 mole and the volume is given 9 .81 liter at the temperature t is equal to 23 degrees celsius.
00:18
We have to find the pressure of this gas.
00:21
So first of all we will convert the temperature into kelvin and this is 23 plus 273 kelvin which is equal to 296 kelvin.
00:31
Now we will apply ideal gas equation pv is equal to nrt where p is the pressure, v is the volume, n is the number of mole, r is the gas constant and t is the temperature.
00:42
So to find the pressure we will rearrange it as nrt divided by v.
00:47
So now we will put the values.
00:49
The number of mole is 23 .5 mole.
00:52
The value of gas constant is 0 .082 litre per mole kelvin.
01:01
And the temperature is 296 kelvin.
01:04
This is divided by volume that is 9 .81 liter.
01:09
So, liter to liter is cut, mole to mole cut and kelvin to kelvin is cut.
01:14
So when we solve the calculation, the pressure of nitrogen gas is equal to 58 .14 atmosphere.
01:26
Now we will solve the second question.
01:29
In the second question, the mass of sulfur dioxide gas is given 28 .6 gram at the temperature 40 degrees celsius and the pressure p is given 850 tor.
01:44
We have to find the volume of this gas.
01:47
So first of all we will convert the temperature into kelvin and this is equal to 40 plus 273 which is equal to 313 kelvin...