A cylindrical-bowl centrifuge is to be used to separate MgSO46·H2O crystals from the mother liquor which comes as a product from a vacuum crystallizer. The centrifugal bowl is 14-in in diameter and 23-in long and carries liquid to a depth of 3 in. It rotates at 3250 rpm. (a) If no crystals smaller than 5 microns in diameter exist in the slurry, what feed rate to the centrifuge will result in complete removal of the solids? Assume that the solid particles do not return to the liquid. Data: density of the solution - 1.21 g/cm3 viscosity of the solution - 1.5 cP density of MgSO46·H2O - crystals 1.66 g/cm3 (b) If the separation were done in the plant using a No. 16 super centrifuge operating at 15,000 rpm, what production rate could be expected?
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The formula for centrifugal force is: Fc = ω^2r where Fc is the centrifugal force, ω is the angular velocity (in radians per second), and r is the radius of rotation. First, we need to convert the bowl dimensions to centimeters: Diameter = 14 in = 35.56 Show more…
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