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The stress in the bar is given by the formula: stress = force / area Show more…
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A bar cross-sectional area $A$ is subjected two equal and opposite tensile forces at its ends as shown in figure. Consider a plane $B B^{\prime}$ making an angle $\theta$ with the length. The ratio of tensile stress to the shearing stress on the plane $B B^{\prime}$ is (a) $\tan \theta$ (b) $\sec \theta$ (c) $\cot \theta$ (d) $\cos \theta$
A bar with cross-sectional area $A$ is subjected to equal and opposite tensile forces $\vec{F}$ at its ends. Consider a plane through the bar making an angle through the bar making an angle $\theta$ with a plane at right angles to the bar (Fig. 11.64$)$ . (a) What is the tensile (normal) stress at this plane in terms of $F, A,$ and $\theta ?(b)$ What is the shear (tangential) stress at the plane in terms of $F, A,$ and $\theta ?$ (c) For what value of $\theta$ is the tensile stress a maximum? (d) For what value of $\theta$ is the shear stress a maximum?
Amit S.
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