a dart is inserted into a spring lodead dart gun and is pushing the spring by a distance x. The 2nd loading pushes the spring a distance 2x. How much faster does 2nd leave the gun than the first
Added by James S.
Step 1
The potential energy (PE) stored in a compressed spring is given by the formula: \[ PE = \frac{1}{2} k x^2 \] where \( k \) is the spring constant and \( x \) is the compression distance. Show more…
Show all steps
Your feedback will help us improve your experience
Sri K and 55 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A dart is loaded into a spring-loaded toy dart gun by pushing the spring in by a distance 'd'. For the next loading, the spring is compressed a distance two times 'd'. If the dart is shot straight up, how much higher will the dart travel the second time compared to the first? a. 4 times as high b. 1/4 as high c. 1/2 as high d. 2 times as high e. the same height
Sri K.
Jiva Y.
A spring gun shoots out a plastic ball at speed v. The spring is then compressed twice the distance it was on the first shot. a) By what factor is the spring's potential energy increased? Explain. b) By what factor is the ball's speed increased? Explain.
Dominique Jan T.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD