A diabetic patient's insulin drip is prepared with 100.0 units of insulin in 500.0 mL normal saline. How many mL normal saline/hr will the drip have to run to deliver 2.00 units insulin/hr?
Added by Francisco Jose H.
Close
Step 1
This is done by dividing the total units of insulin by the total volume of saline. 100.0 units / 500.0 mL = 0.2 units/mL Show more…
Show all steps
Your feedback will help us improve your experience
David Collins and 96 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Ronald P.
An adolescent is admitted to the ICU in diabetic ketoacidosis. The physician orders a continuous insulin infusion of 100 U NPH insulin in 500 mL normal saline. What is the concentration of the infusion?
Jenny W.
You need $500 . \mathrm{mL}$ of a $5.0 \%$ (m/v) glucose solution. If you have a $25 \%$ (m/v) glucose solution on hand, how many milliliters do you need?
Solutions
Dilution of Solutions
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD