Given that $\Phi_E = (8.0 \times 10^3 V \cdot m/s^3)t^3$, we can differentiate this with respect to time to get:
$\frac{d\Phi_E}{dt} = 3 \times (8.0 \times 10^3 V \cdot m/s^3)t^2$
Substituting this into the equation for $I_D$ gives:
$I_D = \epsilon \times 3
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