00:01
Hi, this is a question based on diesel engine.
00:02
So these are the given in the question.
00:04
Now in first step we have to find the stroke volume.
00:08
So stroke volume is equal to vs is equal to pi by 4 into d square into l.
00:16
So on substitution, so vs is equal to 5 by 4 into 20 square into 30 which is equal to 9424 .5 centimeter cube.
00:31
In the next step we have to have to find compression ratio.
00:35
So compression ratio is given by r is equal to vs plus vc divided by vc on substitution.
00:47
So vs is 944 .5 plus 420 divided by 420 which is equal to so compression ratio is r is equal to 23 .4 .3.
01:01
In the third step we have fuel injected at the 5 % of the stroke volume.
01:06
So cut -off takes place at 5 % of stroke volume.
01:21
Therefore, v3 will be equal to 0 .05 into vs plus v2 or v3 will be equal to 0 .05 into vs is v1 minus v2 plus v2 or v3 minus v2 or v3 minus v2 will be equal to 0 .05 into vs is v1 minus v2 plus v2 or v3 minus v2 will be equal to 05 into 0 .05 into vs...