A diode has IS = 10^(-16) A and n = 1. (a) What is the diode voltage if the diode current is 250 μA at T = 25°C? (b) What is the diode voltage at T = 85°C? Assume the diode voltage temperature coefficient is -2 mV/K at 55°C.
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Step 1
The thermal voltage can be calculated using the formula: Vt = kT/q where k is the Boltzmann constant (1.38 × 10^(-23) J/K), T is the temperature in Kelvin, and q is the elementary charge (1.6 × 10^(-19) C). For T = 25°C, we have: Vt_25 = (1.38 × 10^(-23) J/K × Show more…
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