A dip needle vibrates in the vertical plane perpendicular to the magnetic meridian. The time period of vibration is found to be 2 seconds. The same needle is then allowed to vibrate in the horizontal plane and the time period is again found to be 2 seconds. Then the angle of dip is
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Step 1
Step 1: The time period of vibration in the vertical plane is given as 2 seconds, so T_vertical = 2 seconds. Show more…
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A dip needle vibrates in the vertical plane perpendicular to magnetic meridian. The time period of vibration is found to be $2 \mathrm{~s}$. The same needle is then allowed to vibrate in the horizontal plane and time period is again found to be 2 . Then the angle of dip is (a) $0^{*}$ (b) $30^{*}$ (c) $45^{\circ}$ (d) $90^{*}$
Magnetostatics
Round 2
The time of vibration of a dip needle vibrating in the vertical plane is 3s. When magnetic needle is made to vibrate in the horizontal plane, the time of vibration is $3 \sqrt{2}$ s. Then the angle of dip is (a) $30^{\circ}$ (b) $45^{\circ}$ (c) 60 (d) $90^{\circ}$
Round 1
A magnet oscillating in a horizontal plane has a time period of 2 second at a place where the angle of dip is 30o and 3 seconds at another place where the angle of dip is 60o . The ratio of resultant magnetic fields at the two places is
Aakash G.
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