A discrete random variable X has the cdf as follows F(x) = 0 x < 0 0.06 0 ? x < 1 0.19 1 ? x < 2 0.39 2 ? x < 3 0.67 3 ? x < 4 0.92 4 ? x < 5 0.97 5 ? x < 6 1 x ? 6 Calculate a. [4 points] The probability mass function (pmf) f(x) b. [3 points] P(X > 3) c. [3 points] P(2 < X ? 5)
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06 f(1) = 0.19 - 0.06 = 0.13 f(2) = 0.39 - 0.19 = 0.20 f(3) = 0.67 - 0.39 = 0.28 f(4) = 0.92 - 0.67 = 0.25 f(5) = 0.97 - 0.92 = 0.05 f(6) = 1 - 0.97 = 0.03 Show more…
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