A discrete random variable x has the the following probability distribution X 1 2 3 4 5 P(X=x) 3k^2 k 2k^2 2k k Find the value of k?
Added by Mar S.
Step 1
So, we can write the equation: 3k^2 + k + 2k^2 + 2k + k = 1 Now, let's simplify the equation: (3k^2 + 2k^2) + (k + 2k + k) = 1 5k^2 + 4k = 1 Now, let's solve for k: 5k^2 + 4k - 1 = 0 This is a quadratic equation, and we can solve it using the quadratic Show more…
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