00:01
To solve this problem let us write the given data first.
00:06
So here the value of mass of block is given as 3 kg, mass of disc is equal to 5 kg and r is equal to 0 .3 meter.
00:21
Now drawing the free body diagram first.
00:24
So the free body diagram looks like this.
00:27
Here tension is working in this direction and here weight is working in this direction, acceleration is in this direction.
00:35
So you can write the expression as summation of f net is equal to ma or mg minus t is equal to ma let it be equation number 1.
00:49
Rope is not slipping on the disc.
00:52
So also you can write the expression as r alpha is equal to a let it be equation number 2.
01:01
Now also we know that i is equal to moment of inertia which is equal to m r square by 2 let it be equation number 2, moment of inertia of disc about point o.
01:13
Now on further simplification you can write the expression as t multiplication r is equal to i alpha or tr is equal to m r square by 2 multiplication alpha...