00:01
So using equation for 1014, we should first use find rather the angular acceleration.
00:08
So we can say omega final squared equals omega initial squared plus two alpha times delta theta.
00:17
We can say that alpha would then be equal to 15 revolutions per second quantity squared minus 10 revolutions per second quantity squared divided by two times.
00:32
The change in angular displacement, 60 revolutions.
00:37
This is going to be equal to 1 .04 revolutions per second squared.
00:47
And for part b, we can then find delta t.
00:52
So we can say that delta theta equals one half omega initial plus omega final times delta t.
01:03
Therefore, delta t would simply be equal to.
01:07
To the change in angular displacement, or other two times the change in angular displacement, two times 60 revolutions divided by 10 revolutions per second plus 15 revolutions per second.
01:34
And this is giving us approximately 4 .8 seconds.
01:38
At this point for part c, we can see the time taken to reach 10 revolutions per second...