00:01
Hello student, let's solve this question.
00:02
Fundamental frequency of first string f1 is equal to f1 is equal to 366 huts and fundamental frequency of second string f2 is equal to 500 huts now a part now a part now a part second harmonic of first string f1 2 2 is equal to 2 b divided by 2 l 2 b divided by all this is equal to f1 this is equal to f1 this is equal to 2 multiply 366 now this is equal to 732 hertz.
00:33
Now b part, the two string have same length, same tension.
00:38
F1 is equal to f1 is equal to v1 upon 2l, this is equal to 1 divided by 2l root t divided by t divided by mu1.
00:50
This is equal to 1 by 2l, 1 divided by 2l, root tl divided by m1.
00:58
F2.
00:59
F2 is equal to v2 divided by 2l.
01:04
Now this is equal to 1 divided by 2l root t divided by mu 2.
01:09
Now this is equal to 1 divided by 2l , now f1 divided f 2 is equal to root m2 divided m1, m2 divided by m1...