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Hi there.
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So for this problem we are told that a drag racer accelerates with an acceleration that is constant and that acceleration is 90 feet per second square.
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So we need to assume that the initial speed is equal to zero and also its initial position is equal to zero.
00:29
So for part a of this problem, we need to determine and graph the position function for the time greater or equal than zero.
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So we know that in this case, the only thing that we have is a positive acceleration.
00:56
So we need to graph the position with respect to the time.
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Now we can see we are given.
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That it starts at zero, so it starts here at the origin.
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And then because the acceleration is positive, it's going to be a graph of this form.
01:16
And this is because the acceleration is greater than zero.
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So that's a solution for part a of this problem.
01:26
Now for part b, we are asked about how far does the razor travel in the first six seconds? so for that we need first to obtain.
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So we know that the position is the position in this case is just going to be given by the initial position, which we know is zero.
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And this times the speed, the initial speed that we also know it is also equal to zero.
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And this time and this a term that is related by the assessment.
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We know that there is 1 divided by 2 times the acceleration times the time square.
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So we substitute the acceleration that we have in here, which is 90 feet per second square.
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And this times the time square.
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So we need to answer the question of how far does the race of travel in the first six seconds? so we just need to evaluate this function at 6 seconds.
02:51
That will be 1 divided by 2 times 90 feet per second.
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That times the times 6 seconds to the square.
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So from this we obtain a value of 1 ,620 feet.
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So that's a solution for part b of this problem.
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Now for part c, we are asked about, now, at this rate, how long will it take the razor to travel 1 divided by 3 miles? so in this case, the distance travel that we are given in this case at the time that we need to determine is 1 divided by 3 miles.
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Now we need to pass this into feet.
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So what we can do is to multiply this by a factor of conversion...