00:01
In this problem, we're looking to draw chiral molecules that match different descriptions.
00:08
So first, we have a chloroalkane, and we want to find what's called degrees of unsaturation.
00:16
This will tell us if there's double bonds or rings, and this can also be triple bonds, so it really tells you if you have pi bonds.
00:23
So we take 2, time the number of carbons, add 2, subtract the number of hydrogens and halogens, divide by 2, so we get 0.
00:34
So there's not going to be a rain or a pie bond.
00:37
So we have 1, 2, 3, 4, 5 carbons.
00:42
And let's say we put a chlorine here.
00:47
And we want to make sure we have the right number of hydrogens.
00:51
So we have 3, 4, 6, 8, 11.
00:56
So this would be one example of a chiral molecule with that description.
01:02
Then we have an alcohol, c6h14o.
01:08
Again, we'll look at degrees of unsaturation.
01:10
2 times the number of carbons.
01:12
Add 2.
01:14
Subtract the number of hydrogens.
01:15
Divide by 2.
01:16
Again, we get 0...