Question

A drop of mercury has a volume of 22.0 µL and a density of 13.55 g/cm$^3$. How many atoms of mercury are contained within this drop? 8.95\times 10^{20} at

          A drop of mercury has a volume of 22.0 µL and a density of 13.55 g/cm$^3$.
How many atoms of mercury are contained within this drop? 8.95\times 10^{20} at

A drop of mercury has a volume of 22.0 µL and a density of 13.55 g/cm^3.
How many atoms of mercury are contained within this drop? 8.95×10^20 at

Added by Ramon G.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Ma Ednelyn Lim

02/24/2022

Step 1

Given: Volume = 22.0 μL = 22.0 × 10^-6 m^3 Density = 13.55 g/cm^3 = 13550 kg/m^3 Using the formula: Mass = Density × Volume Mass = 13550 kg/m^3 × 22.0 × 10^-6 m^3 Mass = 0.2971 × 10^-3 kg Mass = 0.2971 g Show more…

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A drop of mercury has a volume of 22.0mu L and a density of 13.55(g)/(c)m^(3). How many atoms of mercury are contained within this drop? A drop of mercury has a volume of 22.0 uL and a density of 13.55 g/cm3 How many atoms of mercury are contained within this drop? 8.95x1020 ai